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Harman [31]
3 years ago
12

1. 3(x+15)=572. 2(x-9)=263. 4(x-12)=-32

ormula1" title="solve \: for \: x" alt="solve \: for \: x" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
White raven [17]3 years ago
3 0

Step-by-step explanation:

1)3(x+15)=57

3x+45=57

3x=57-45

3x=12

x=12/3.

x=4

2)2(x-9)=26

2x-18=26

2x=26+18

2x=44

x=44/2

x=22

3)4(x-12)=-32

4x-48=-32

4x=-32+48

4x=+16(greater number sign)

x=16/4

x=4

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Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0
3 years ago
What is the variance of the data set? 8, 9, 10, 16, 17
adoni [48]
Mean = (8 + 9 + 10 + 16 + 17) / 5 = 60/5 = 12.

x - mean:

8 - 12 = -4,  -4² = 16

<span>9 - 12 = -3,  -3² = 9
</span>
<span>10 - 12 = -2,  -2² = 4
</span>
<span>16- 12 = 4,  4² = 16</span>

<span>17- 12 = -5,  -5² = 25
</span>
Sum of the squares =   16 + 9 + 4 + 16 +25 = 70

Variance = 70/5 = 14

Variance = 14
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Step-by-step explanation:

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