The ground temperature at an airport is 15 °C. The temperature decreases by 5.8 °C for every increase of 1 kilometer above the g
round. What is the temperature outside a plane flying at an altitude of 5 kilometers?
1 answer:
44 because if you use the equation y=mx+b you would plug in 5.8(5)+15 which equals 44
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Answer:
7√2
Step-by-step explanation:
Thank to the give angle we can say that the two legs are congruent
b = 
98/2 = 49
49/7 = 7
7/7 = 1
98 = 7^2 x 2
√98 = 7√2
Answer:
Plug in the numbers in the table to find the pattern.
Step-by-step explanation:
Answer:
Step-by-step explanation:
11x+6 = 15x-26
1 mile = 1760 yards
Therefore you must times 13 by 1760
13x1760 = 22880

so,

it equals 12.49 or 12.5 depending on rounding
I hope this helps!