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3 years ago

I need help with this question.

Mathematics

1 answer:

Alborosie3 years ago

5 0

Answer:

2116

Step-by-step explanation:

hope this helps :)

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Use the order of operations and the digits 2,4,6 and 8 to create an expression with a value of 2

Anvisha [2.4K]

<span>8 / 2 + 4 - 6 = 2.

Hope I Helped You!!! :-)

Have A Good Day!!!</span>

4 0

3 years ago

I need some help pls :'(

Luda [366]

Answer:

Step-by-step explanation:

4 0

3 years ago

Determine the domain and range of the function f(x)= 3x+2. Also, state the intervals where the function f(x)= 3x+ 2 is increasin

aev [14]

Answer:

Increasing on it's domain $(-\infty,\infty)$ because the slope is positive.

The domain and range are both all real numbers, also known as

$(-\infty,\infty)$ .

Step-by-step explanation:

All domain really means is what numbers can you plug in and you get number back from your function.

I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.

The domain is all real numbers.

In interval notation that is $(-\infty,\infty)$ .

Now the range is the set of numbers that get hit by y=3x+2.

Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.

If slope is positive, then the line is increasing.

If slope is negative, then the line is decreasing.

So y=3x+2 hits all values of y because it is increasing forever. The range is all real numbers. In interval notation that is $(-\infty,\infty)$ .

3 0

3 years ago

A farmer has 90 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wid

Leya [2.2K]

Answer:

W = 15 ft. and L = 30 ft.

Step-by-step explanation:

Perimeter = 90 ft.

Twice as long as it is wide: L=2W

P = 2(L + W) = 2(2W + W) = 6W

90 = 6W

W = 15 ft. and L = 30 ft.

6 0

3 years ago

Read 2 more answers

Rewrite the expressions in each pair so that they have the same base. c) (1 /2)^2x and (1/ 4)^x - 1

just olya [345]

I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.

7 0

4 years ago