The function is illustrated below based on the information.
<h3>How to describe the function?</h3>
When x <= 8000
The cost remains constant at 0.35 when x increases from 0 to 8000. The slope of the cost function over this part is 0
When 8000 < x <= 20000
The cost remains constant at 0.75 when x increases from 8000 to 20000 and the slope of the cost function over this part is 0.
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Answer:
$20.11 (assuming S325 was meant to be $3.25)
Step-by-step explanation:
50.00 - 5.52 = 44.48
44.48 - 3.25 = 41.23
41.23 -21.12 = 20.11
Hope this helps <3
Answer:
There is not sufficient evidence to support the claim that the technique performs differently than the traditional method.
Step-by-step explanation:
The null hypothesis is:

The alternate hypotesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A researcher used the technique with 260 students and observed that they had a mean of 94 hours. Assume the standard deviation is known to be 6.
This means, respectively, that 
The test-statistic is:



The pvalue is:
2(P(Z < -2.69))
P(Z < -2.69) is the pvalue of Z when X = -2.69, which looking at the z-table, is 0.0036
2*(0.0036) = 0.0072
0.0072 < 0.01, which means that the null hypothesis is accepted, that is, there is not sufficient evidence to support the claim that the technique performs differently than the traditional method.
Your question is incomplete, but I am guessing that it reads something like:
“Diego has run 4/5 of a race distance. He has run 7 2/3 miles. How long is the race? Or “how many miles does he have left?”
How long is the race? = 9 7/12 miles
4/5x = 7 2/3
4/5x = 23/3
x = 23/3 • 5/4
x = 115/12
x = 9.58333
x = 9 7/12 miles
How many miles does he have left? = 1 1/12 miles
1/5 • 115/12 = 115/60 = 1.916666
= 1 55/60 = 1 11/12 miles
Let me know if I didn’t guess your question correctly and I will try to help more.
Answer:
- a) p(10) ≈ 48.10
- b) about 1.00 million/year
Step-by-step explanation:
a) Use t=10 in the given formula and do the arithmetic.
39.07×1.021^10 ≈ 48.0951 ≈ 48.10 . . . millions
__
b) The derivative of p(t) is ...
p'(t) = p(t)·ln(1.021) ≈ 0.8120·1.021^t
p'(10) ≈ 0.99954 ≈ 1.00 . . . . millions per year