Answer:
2 points throw = 37
3 points throw = 11
Step-by-step explanation:
Given that:
Let number of
2 points = x ; 3 points = y
x + y = 48 - - - (1)
2x + 3y = 107 ---(2)
x = 48 - y
Then ;
2(48 - y) + 3y = 107
96 - 2y + 3y = 107
96 + y = 107
y = 107 - 96
y = 11
From (1)
x = 48 - 11
x = 37
2 points throw = 37
3 points throw = 11
Answer:
Step-by-step explanation:
We observe that the difference of terms is 4, 7 and 15 and next level difference is 4. It means the sequence is quadratic.
<u>We can compare this with simple quadratic sequence </u>
<u>and find out that doubling each term gives us </u>
This is close to our sequence, write the terms as follows to find exact rule
<u>The first term: </u>
- a₁ = 4 = 2*1² + 2 = 2*1² + 1 + 1
<u>The second term</u>
- a₂ = 11 = 2*2² + 3 = 2*2² + 2 + 1
<u>The third term:</u>
- a₃ = 22 = 2*3² + 4 = 2*3² + 3 + 1
<u>The fourth term:</u>
- a₄ = 37 = 2*4² + 5 = 2*4² + 4 + 1
<u>The nth term as per observation above is:</u>
Answer:
Los números naturales incluyen solo enteros positivos y comienzan desde 1 hasta infinito
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
#SPJ9
