A computer can manipulate symbols as if it understands the symbols and is reasoning with them, but in fact it is just following
1 answer:
Answer:
The symbols may or may not have meaning, but the machine does not need to know how the symbols are interpreted in order to manipulate the symbols in the right way.
Explanation:
The computer can change the symbols in the case when the computer understand but in actual following the cut-paste rules without having any understanding this is because the symbols might be have meaning or not but if we talk about the machine so actually they dont know how the symbols are interpreted and how it can be used so that it can be change in the accurate way
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Answer:
The pressure gauge reading will be;
12 psi
Explanation:
The question relates to relationship of pressure and area
The given parameters for the measurement are;
The weight of the load = 60 lb
The required area of the piston = 5 in.²
Pressure exerted by a force can be defined as follows;
The weight of the load = The force applied by the load
Therefore;
The gauge reading will be 12 psi.
Answer:
The code is given as follows,
Explanation:
Code:
#include <stdio.h>
#include <string.h>
int n; //to store size of array
char* ArrayChallenge(int arr[]) //function returns string true or false
{
int i, j;
int sum = 0;
for(i = 0; i < n; i++)
{
sum = sum + arr[i]; //count sum
}
for(i = 0; i < n; i++)
{
for(j = i+1; j < n; j++) //loop for every two elements in array
{
if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum
{
printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);
return "true"; //If proudct of two elements > 2 times sum. return true
}
}
}
return "false"; // If proudct of two elements < 2 times sum. return false
}
int main()
{
printf("\nEnter size of array: ");
scanf("%d", &n); //read size of array
int A[n]; //array of size n
printf("\nEnter array elements: ");
int i;
for(i = 0; i < n; i++)
{
scanf("%d", &A[i]); //read array from stdin
}
printf("%s\n",ArrayChallenge(A)); //ccall function and print answer
return 0;
}
