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arsen [322]
3 years ago
10

A 10kg mass is moving to the right with a velocity of 15 m/s. A 13kg mass

Physics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

M1u1+(-m2u2) = (m1+m2) V. By using this equation you can find the final velocity of that. It would be 3.13ms-1. And the direction is right side.

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soldier1979 [14.2K]

Answer:

marblebrainiest plz\c cmarble

Explanation:

8 0
3 years ago
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A wildlife researcher is tracking a flock of geese. the geese fly 3.5 km due west, then turn toward the north by 40 ∘ and fly an
kaheart [24]

To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

 

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

 

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

θ = 180 – 40 = 140°

 

c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140

c^2 = 56.63

c = 7.53 km

 

<span>So the magnitude of the displacement is 7.53 km</span>

4 0
3 years ago
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What is it when you divide the total distance traveled by the total time
alexdok [17]

This is called average speed.Its really simple

4 0
3 years ago
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A rectangular plate has a length of (21.7 ± 0.2) cm and a width of (8.2 ± 0.1) cm. Calculate the area of the plate, including it
Grace [21]

Answer:

(177.94 ± 3.81) cm^2

Explanation:

l + Δl = 21.7 ± 0.2 cm

b + Δb = 8.2 ± 0.1 cm

Area, A = l x b = 21.7 x 8.2 = 177.94 cm^2

Now use error propagation

\frac{\Delta A}{A}=\frac{\Delta l}{l}+\frac{\Delta b}{b}

\frac{\Delta A}{A}=\frac{0.2}{21.7}+\frac{0.1}{8.2}

\Delta A=177.94 \times \left ( 0.0092 + 0.0122 \right )=3.81

So, the area with the error limits is written as

A + ΔA = (177.94 ± 3.81) cm^2

8 0
3 years ago
An electric field of intensity 3.7 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.3
jekas [21]

Answer:

a)906.5 Nm^2/C

b) 0

c) 742.56132 N•m^2/C

Explanation:

a) The plane is parallel to the yz-plane.

We know that

flux ∅= EAcosθ

3.7×1000×0.350×0.700=906.5 N•m^2/C

(b) The plane is parallel to the xy-plane.

here theta = 90 degree

therefore,

0  N•m^2/C

(c) The plane contains the y-axis, and its normal makes an angle of 35.0° with the x-axis.

therefore, applying the flux formula we get

3.7×1000×0.3500×0.700×cos35°= 742.56132 N•m^2/C

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