3 years ago

A 10kg mass is moving to the right with a velocity of 15 m/s. A 13kg mass

1 answer:

7 0

Answer:

M1u1+(-m2u2) = (m1+m2) V. By using this equation you can find the final velocity of that. It would be 3.13ms-1. And the direction is right side.

You might be interested in

The energy a sled has when you pull it back up a hill is best described as

yawa3891 [41]

The answer is d because you are using energy to pull the sled back up, which is mechanical energy

5 0

3 years ago

Derek owns a farm that produces soybeans, avocados, and pecans. What is the word used to describe these items?

Novosadov [1.4K]

Answer:

crops

Explanation:

dairy are milk products and those aren’t

live stock is domesticated farm animals raised to produce resources

non-perishables are canned food and dried food. they can last a long time. they don’t need to be refrigerated or

7 0

3 years ago

Read 2 more answers

Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s

tatyana61 [14]

Answer:

$Q_T=63313.5\ J$

Explanation:

Given:

temperature of skin, $T_s=34^{\circ}C$

initial temperature of steam vapour, $T_v=100^{\circ}C$

latent heat of steam, $L=2256\ J.g^{-1}$

mass of steam, $m=25\ g$

specific heat of water, $c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}$

final temperature, $T_f=34^{\circ}C$

Assuming that no heat is lost in the surrounding.

We know:

$Q=m.c.\Delta T$

Now the total heat given by the steam to form water at the given conditions:

$Q_T=Q_{Lv}+Q_w$ ..............................(1)

where:

$Q_{Lv}=$ latent heat given out by vapour to form water of 100°C

$Q_w=$ heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

$Q_T=m(L+c.\Delta T)$

$Q_T=25(2256+4.19\times 66)$

$Q_T=63313.5\ J$

is the heat transferred to the skin.

4 0

3 years ago

Omar observes that many buildings in his city were built using limestone. He has read that acid rain can damage limestone. He al

Softa [21]

Answer:he conducts the investigation to see the effect acidic water has on limestone

Explanation:

6 0

3 years ago

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag

statuscvo [17]

P=M÷V
p=28.7÷5.74
p=5

The density is 5.

8 0

3 years ago

Read 2 more answers