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Verizon [17]
3 years ago
6

Cindy runs 2 kilometers every morning. she takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minu

te for the next 350 meters, and 3 minutes for the rest.
Physics
1 answer:
SpyIntel [72]3 years ago
3 0
2000-250-1000-350=400

the rest is 400 meters
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WHY does an acceleration cause velocity to increase
harkovskaia [24]

Answer:

When the velocity of an object changes it is said to be accelerating. Acceleration is the rate of change of velocity with time. ... Acceleration occurs anytime an object's speed increases or decreases, or it changes direction.

5 0
3 years ago
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Billy drops a water balloon from the roof of his house. Since the balloon began with an original velocity of zero how far above
VashaNatasha [74]
T=2,5s
a=g≈10m/s²

h=s=?

s= \frac{1}{2} at^2 \Leftrightarrow h=\frac{1}{2}gt^2=\frac{1}{2}*10m/s^2 *(2,5s)^2=5m/s^2* \frac{25}{4} s^2=\boxed{31,25m}



"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."


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7 0
3 years ago
A capacitor of capacitance C has charge Q and stored energy is U if the charge is increased to 2Q then energy will be A)4U B)2U
Lubov Fominskaja [6]

Answer:

2u

Explanation:

2u

W = Vq

q = CV

W = V.CV

W = CV²

W/C = V²

V = √(W/C)

√(W1/C1) = √(W2/C2)

√(u/c) = √(x/2c)

x = 2u

8 0
3 years ago
Identify the positive and negative about trade blocs.
ohaa [14]

Answer:

if this is on odyssey ware then i can edit my answer to help you

Explanation:

5 0
3 years ago
The car's initial speed was 15 m / s and the distance the car travels before it comes to a complete stop after the driver applie
pentagon [3]

Initial speed of the car (u) = 15 m/s

Final speed of the car (v) = 0 m/s (Car comes to a complete stop after driver applies the brake)

Distance travelled by the car before it comes to halt (s) = 63 m

By using equation of motion, we get:

\bf \longrightarrow  {v}^{2}  =  {u}^{2}  + 2as \\  \\ \rm \longrightarrow  {0}^{2}  =  {15}^{2}  + 2 \times a \times 63 \\  \\ \rm \longrightarrow 0 = 225 + 126a \\  \\ \rm \longrightarrow 126a =  - 225 \\  \\ \rm \longrightarrow a =  -  \dfrac{225}{126}  \\  \\ \rm \longrightarrow a =  - 1.78 \: m {s}^{ - 2}

\therefore Acceleration of the car (a) = -1.78 m/s²

Magnitude of the car's acceleration (|a|) = 1.78 m/s²

5 0
3 years ago
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