Explanation:
It is given that, your boss tells you that she needs a decision by the end of the day about the machine you want to purchase for your new operation.
Option 1.
This $5,000 machine is supplied energy at a rate of 1,900 W and does useful work at a rate of 1,786 W.
Efficiency = (output power/ input power) × 100
Here, output power is 1786 W and input power is 1900 W
So, ![\eta=\dfrac{1786}{1900}\times 100=94\%](https://tex.z-dn.net/?f=%5Ceta%3D%5Cdfrac%7B1786%7D%7B1900%7D%5Ctimes%20100%3D94%5C%25)
Option 2.
This $4,500 machine is supplied energy at a rate of 1,450 W and does useful work at a rate of 1,300 W.
Efficiency = (output power/ input power) × 100
Here, output power is 1300 W and input power is 1450 W
So, ![\eta=\dfrac{1300}{1450}\times 100=89\%](https://tex.z-dn.net/?f=%5Ceta%3D%5Cdfrac%7B1300%7D%7B1450%7D%5Ctimes%20100%3D89%5C%25)
Option 3.
This $4,750 machine is supplied energy at a rate of 1950 W and does useful work at a rate of 1833 W.
Efficiency = (output power/ input power) × 100
Here, output power is 1833 W and input power is 1950 W
So, ![\eta=\dfrac{1833}{1950}\times 100=94\%](https://tex.z-dn.net/?f=%5Ceta%3D%5Cdfrac%7B1833%7D%7B1950%7D%5Ctimes%20100%3D94%5C%25)
Option 4.
This $4,750 machine is supplied energy at a rate of 2,000 W and does useful work at a rate of 1,822 W.
Efficiency = (output power/ input power) × 100
Here, output power is 1822 W and input power is 2000 W
So, ![\eta=\dfrac{1822}{2000}\times 100=91.1\%](https://tex.z-dn.net/?f=%5Ceta%3D%5Cdfrac%7B1822%7D%7B2000%7D%5Ctimes%20100%3D91.1%5C%25)
Since, both option (3) and (1) is 94 % but in option (c) the cost is less and is giving maximum efficiency. So, the correct option is (b) " option 3."