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2 years ago

Question 11(Multiple Choice Worth 3 points)

Physics

1 answer:

melomori [17]2 years ago

8 0

Answer:

Explanation:

The only thing that decreases the gravitational pull between 2 objects is if you<u> increase the distance.</u>

The formula is F = G*m*m/r^2

As r^2 gets larger and G and m1 and m2 remain the same, F has to get smaller because r^2 divides into G*m1*m2

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This is in the thermosphere which is at an altitude of 85-520km

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2 years ago

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Answer:

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2 years ago

It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass

vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

$v^{2}=u^{2}+2\cdot a \cdot s$

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/ $Sec^{2}$

s= Distance traveled before stop m

Case 1

u= 13 m/sec, v=0, s= 57.46 m, a=?

$0^{2} = 13^{2} + 2 \cdot a \cdot57.46$

a = -1.47 m/ $Sec^{2}$ (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/ $Sec^{2}$ (since same friction force is applied)

$v^{2} = 29^{2} - 2 \cdot 1.47 \cdot S$

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

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2 years ago

Three systems of two charged particles are shown below. All the particles have the same mass,

Len [333]

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Explanation:

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2 years ago

Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average

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Answer:

9517.2 lbm

Explanation:

Electricity consumption = 14000 kWh/year

Fuel consumption = 900 gal/year

Amount of CO₂ produced per gallon = 26.4 lbm/gal

Amount of CO₂ produced per kWh = 1.54 lbm/kWh

Amount of CO₂ produced in one year

$14000\times 1.54+900\times 26.4=45320\ lbm$

Reduction would be

$0.21\times 45320=9517.2\ lbm$

The reduction in the amount of CO₂ produced is 9517.2 lbm

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3 years ago