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ohaa [14]
3 years ago
5

Two point charges 3q and −8q (with q > 0) are at x = 0 and x = L, respectively, and free to move. A third charge is placed so

that the entire three-charge system is in static equilibrium. What are the magnitude, sign, and x − coordinate of the third
Physics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

Explanation:

The unknown charge can not remain in between the charge given because force on the middle charge will act in the same direction due to both the remaining charges.

So the unknown charge is somewhere on negative side of x axis . Its charge will be negative . Let it be - Q and let it be at distance - x on x axis.

force on it due to rest of the charges will be equal and opposite so

k3q Q / x² =k 8q Q / (L+x)²

8x² = 3 (L+x)²

2√2 x = √3 (L+x)

2√2 x - √3 x = √3 L

x(2√2 - √3 ) = √3 L

x = √3 L / (2√2 - √3 )

Let us consider the balancing force on 3q

force on it due to -Q and -8q will be equal

kQ . 3q / x² = k3q  8q / L²

Q = 8q  (x² / L²)

so charge required = - 8q  (x² / L²)

and its distance from x on negative x side = √3 L / (2√2 - √3 )

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melamori03 [73]

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

P.E = mgh

Substituting into the equation, we have;

P.E = 1*9.8*1.5

P.E = 14.7 Joules.

6 0
3 years ago
Which image shows an example of the strong nuclear force in action?
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i think this is the incomplete page that you are showing but the answer is

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6 0
3 years ago
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thou
Leona [35]

Answer:

F=2.84*10^{-26}N  & -y direction

F=2.84*10^{-26}N & +y direction

Explanation:

From the question we are told that:

Speed of electron V_e=3.83 * 10^5 m/s +x direction

Earths magnetic field B_e=3.04 * 10^-^8 +z direction

a)

Generally the equation for magnetic force F_m is mathematically given by

F=q(V_e*B_e)

where

q=1.6*10^{-19}c\\\=i*\=z=-\=j

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N  -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

\=F'=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N & +y direction

5 0
3 years ago
by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th
xenn [34]

Answer:

<em>The force is now 9 times the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}

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\displaystyle F'=9F

The force is now 9 times the original force

8 0
3 years ago
A stationary police car emits a sound of frequency 1240 HzHz that bounces off of a car on the highway and returns with a frequen
Tju [1.3M]

Answer

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frequency of sound after return  = 1275 Hz

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Using Doppler's effect formula

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v is the speed of the car

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now, inserting the value of equation (1)

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   2.02822 v = 340 x 0.028822

   2.02822 v = 9.799

   v = 4.83 m/s

hence, the speed of the car is equal to v = 4.83 m/s

5 0
3 years ago
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