3 years ago

Enter the equation of the line in slope-intercept form. Enter the answer in fraction form.

Mathematics

1 answer:

snow_lady [41]3 years ago

8 0

Answer:

Step-by-step explanation: this is because you have a negative

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What is the product?(4y − 3)(2y2 + 3y − 5)8y3 + 3y + 158y3 − 23y + 158y3 − 6y2 − 17y + 158y3 + 6y2 − 29y + 15

motikmotik

We need to find the product of :

$\mleft(4y-3\mright)\mleft(2y2+3y-5\mright)$

So, the result as following:

$\begin{gathered} \mleft(4y-3\mright)\mleft(2y^2+3y-5\mright) \\ =4y\cdot(2y^2+3y-5)-3\cdot(2y^2+3y-5) \\ =8y^3+12y^2-20y-(6y^2+9y-15) \\ =8y^3+12y^2-20y-6y^2-9y+15 \\ \\ =8y^3+6y^2-29y+15 \end{gathered}$

So, the answer is the option 4. 8y3 + 6y2 − 29y + 15

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