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3 years ago

What is the slope of the line that passes through points (6, − 2) and (21, 3) ?

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

Answer:

$m=\frac{1}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (6, -2)

Point (21, 3)

Step 2: Find slope m

Substitute: $m=\frac{3+2}{21-6}$
Add/Subtract: $m=\frac{5}{15}$
Simplify: $m=\frac{1}{3}$

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Which point below is not on the graph of p(x) = +36- X?

natka813 [3]

Answer:

We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:

(-13,7)

(-35, 1)

(11,5)

(27,3)

If any of the points belong to the equation, then the equality will be met.

Then:

(-13,7) :

7 = 36 - (-13)

7 = 36 + 13

7 = 49 ❌

(-35, 1) :

1 = 36 - (-35)

1 = 71❌

(11, 5) :

5 = 36 - 11

5 = 25 ❌

(27,3)

3 = 36 - 27

3 = 9 ❌

None of the points belong to the graph. Therefore, all points are NOT on the grah of p(x) = 36 - x.

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3 years ago

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3 years ago

Given the quadratic function : f(x)=x^24x-12 Find the vertex. Can you show the steps?!?

vlada-n [284]

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\\\\
\begin{array}{llcccl}
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&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad 
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3 years ago

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zvonat [6]

$\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{4}}\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
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\qquad 
\begin{cases}
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a=adjacent\\
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\end{cases}
\\\\\\
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