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Alecsey [184]
3 years ago
7

HELP ALMOST CLASS TIME

Mathematics
2 answers:
kondor19780726 [428]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Lesechka [4]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Here are the heights in inches of 10 professional basketball players: 66, 74, 76, 77, 78, 79, 80, 80, 82, 84. The mean of these
Dvinal [7]

Answer:

Question 4: The set has 66 as an outlier and removing it increases the mean by about 1.3 inches.

Question 5: The set has 50 as an outlier and removing it increases the mean by about 3.

Step-by-step explanation:

<u>Question 4:</u><u> </u>

Given heights are:

66, 74, 76, 77, 78, 79, 80, 80, 82, 84

The mean is: 77.6 inches

Removing 66 will make the mean increase to 78.9

So,

<u>The set has 66 as an outlier and removing it increases the mean by about 1.3 inches.</u>

<u>Question 5:</u>

50, 74, 76, 77, 78, 79, 80, 80, 82, 84

The mean is 76.

We can clearly see that 50 is an outlier as it is quite less than the given data.

Calculating mean after removing 50 will give us mean equal to 78.9

So the correct answer is:

<u>The set has 50 as an outlier and removing it increases the mean by about 3.</u>

5 0
3 years ago
The perimeter of a right angled triangle is 56 cm and its hypotenuse is 25 cm. Find the area of triangle.​
Daniel [21]
Perimeter = 56
Hypo = 25
So 56-25 = 31 (for two side)
for one side = 31/2 = 15.5

so area = 1/2 x base x height
6 0
3 years ago
Can someone help me plz
FrozenT [24]

Answer:

I cant see it?

Step-by-step explanation:

3 0
3 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation? Solve x2 = 12x – 15 by completing the s
Svetlanka [38]

Answer: 6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}

Step-by-step explanation:

Given

Quadratic equation is

x^2-12x+15=0

Solving by completing the square method

\Rightarrow x^2-2\cdot 6\cdot x+15=0\\\text{add and subtract 36}\\\Rightarrow x^2-2\cdot 6\cdot x+15+36-36=0\\\Rightarrow x^2-2\cdot 6\cdot x+36+(-36+15)=0\\\text{using}\ (a-b)^2=a^2+b^2-2ab\\\Rightarrow (x-6)^2-21=0\\\Rightarrow (x-6)^2=21\\\Rightarrow x-6=\pm \sqrt{21}\\\Rightarrow x=6\pm \sqrt{21}

The solution set of the equation is 6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}

6 0
3 years ago
Read 2 more answers
Can someone hep me on this
Pavel [41]
5x+4y= $35
x= daisies and y=roses
3x+6y=$39
7 0
3 years ago
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