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Evgen [1.6K]
3 years ago
14

Which characteristic of a sound is affected by the amount of energy used to create that sound? In what direction the sound will

travel how fast or slow the sound travels in a particular medium how high or low the sound's pitch is how loud or soft the sound is
Physics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

The correct option is;

How loud or soft the sound is

Explanation:

The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure

A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.

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I think 30 as that’s usually average speed
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A step-up transformer has 50 turns on its primary coil and 2000 turns on its secondary
ryzh [129]

Answer:

Vs= 6000 v

Ip=9.6 A

Explanation:

Ns/Np = Vs/Vp

2000/50 = Vs/150

40 x 150 = Vs

Vs= 6000 v

Vs/Vp=Ip/Is

6000/150=Ip /0.24

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In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot
Fittoniya [83]

Answer:

Q=7.9\times 10^{-10}\ C

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

A=5\times 10^{-3}\ m^2

We Capacitance given as

For air

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}

C_1=2.2\times 10^{-11}\ F

C_2=\dfrac{K\varepsilon _oA}{d}

C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F

C_2=6.6\times 10^{-11}\ F

Net capacitance

C=C₁+C₂

C=8.8\times 10^{-11}\ F

We know that charge Q given as

Q= C V

Q=12\times 6.6\times 10^{-11}\ C

Q=7.9\times 10^{-10}\ C

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3 years ago
The Köppen classification system is used as a classification system for
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It is used to classify the climates around the world

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4 years ago
Read 2 more answers
A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha
pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

f_n = nf_1

where f_1 is the fundamental frequency.

Here in this case

f_1 = 409 Hz

A person is capable to hear frequencies up to

f = 1.00 \cdot 10^4 Hz

So the highest harmonics that can be heard by a human can be found as follows:

f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24

8 0
3 years ago
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