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Kaylis [27]
3 years ago
11

It appears as though the moon disappears and the sun comes out in the daytime. Based on what you know, explain why this is happe

ning in the daytime.
Earth is rotating toward the sun.


Earth is rotating away from the sun.

The moon is rotating away from the sun.

The moon is rotating towards the sun.
Physics
2 answers:
atroni [7]3 years ago
8 0
The Earth is rotating toward the sun and away from the moon. Because of this, part of the Earth’s hemisphere sees daylight while the other part is not able to.
zimovet [89]3 years ago
6 0

Answer:

The Earth is toward the sun

Explanation:

DONT LISTEN TO ME I AM A CHILD AND I JUST GUESSED

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Let x define the position of an object such that x =
timama [110]
See the attached picture for answers

7 0
3 years ago
A source of sound is kept in a jar in a vacuum. Air is slowly introduced in to the jar. What happens to the sound coming out of
timama [110]
<span>The loudness of the sound increases gradually as the air is slowly introduced in to the jar. This is because sound needs a physical medium and in a vacuum there is none. The air provides that medium and as it is introduced, the transfer of sound energy increases</span>
3 0
3 years ago
Find the value of 15.0 n in pounds. use the conversions 1slug=14.59kg and 1ft=0.3048m.
Wewaii [24]
15 N = 15  kg m / s² = 
= 15 · 1/14.59  slug · 1 / 0.3048 =
= 15 · 0.06854 · 3.24254 = 
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5 0
3 years ago
An 800-kHz radio signal is detected at a point 2.7 km distant from a transmitter tower. The electric field amplitude of the sign
dimaraw [331]

Answer:

Option D is correct: 170 µW/m²

Explanation:

Given that,

Frequency f = 800kHz

Distance d = 2.7km = 2700m

Electric field Eo = 0.36V/m

Intensity of radio signal

The intensity of radial signal is given as

I = c•εo•Eo²/2

Where c is speed of light

c = 3×10^8m/s

εo = 8.85 × 10^-12 C²/Nm²

I = 3×10^8 × 8.85×10^-12 × 0.36²/2

I = 1.72 × 10^-4W/m²

I = 172 × 10^-6 W/m²

I = 172 µW/m²

Then, the intensity of the radio wave at that point is approximately 170 µW/m²

7 0
3 years ago
In the circuit shown below, the battery voltage is 20 volts. What will be the reading of the ammeter shown in the circuit? Two-r
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Answer: 0.40 amperes

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4 years ago
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