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vagabundo [1.1K]
3 years ago
5

Help please, i will mark brainliest.

Chemistry
1 answer:
ki77a [65]3 years ago
5 0

Answer:

you tube

Explanation:

HI

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Consider the titration of 10.00 mL of a monoprotic weak acid with 0.1234 M NaOH. If the equivalence point volume of NaOH was det
gogolik [260]

The initial concentration of the unknown acid is 0.1900 M.

Explanation:

Titration is a chemical method of analysis to know the concentration and volume of the unknown chemical or analyte.

The formula for the titration is:

Macid x Vacid = Mbase x V base

The volume must be in litres. The volume is given in ml it should be divided with 1000 to obtain values in litre.

Data given are:

volume of acid= 10 ml 0.01 L

Molarity of the acid = ?

volume of the NaOH or base = 15.4 ml or 0.0154 L (equivalence point of the base)

molarity of the base = 0.1234 M

Applying the formula and putting the values, we get

Macid x 0.01 = 0.1234 x 0.0154

Macid =  0.1900 M

The weak acid is having molarity of 0.1900 M against the strong base with molarity of 0.1234M.

4 0
2 years ago
Large crystals are made from the slow cooling of magma. <br> a. True<br> b. False
Step2247 [10]
I would have to say the answer is a. True.
5 0
3 years ago
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How many moles of C6Cl6 are in 5.44g
Kazeer [188]

Explanation:

rbrhrhyhggggsdffffffffffv

4 0
3 years ago
PPPPPPPPLLLLLLLLLLLLLLZZZZZZZZZZ HELP ME ITS ALREDY OVER DUE PLZ HELP ME PPPLLLZZZ I NEED IT IM DESPRET
nikitadnepr [17]

Answer:

1) Big Bang Theory

2) we are in a phase of the big bang theory

Explanation:

So for number 1 the answer is the -big bang theory- and number 2 there is a theory that pretty much says that were in a constant cycle. what I mean is theoretically in a couple million years the entire universe will form together again into another dense ball and repeat the process. So basically the universe is still in the "expanding phase" and that's what backs up the theory of the big bang (the fact that were in one of the big bang theory's "phases")

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6. The given mass of helium occupies
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Answer:

V2 = 35.967cm^3

Explanation:

Given data:

P1 = 0.2atm

P2 = 1.4atm

V1 = 250cm^3

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T2 = 12°C + 273 = 285K

Apply combined law:

P1xV1/T1 = P2xV2/T2 ...eq1

Substituting values:

0.2 x 250/283 = 1.4 x V2/285

Solve for V2:

V2 = 14250/396.2

V2 = 35.967cm^3

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