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mars1129 [50]
3 years ago
12

1)¿Como estoy siendo responsable con el cuidado de mi salud y de los demás , ya sea en casa o si algo a realizar alguna activida

d , para evitar el contagio?
Chemistry
1 answer:
erica [24]3 years ago
4 0

Answer:

The most effective strategy to control the spreading of some infections is through social distancing.

Explanation:

Since we don't have an effective treatment to stop the infection of some pathogens including the recent pandemic SARS-Cov 2 virus, it is imperative to prevent it from spreading

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1+1 hahahahahhhahahaahahahahahahahahahahahahahaha why u dumb
-Dominant- [34]

Answer:

1+1=2 Unless this is a trick question. Then it's most likely 11.

Explanation:

4 0
2 years ago
Read 2 more answers
Pl help me, i need a good grade on this.
Blizzard [7]
1. Option A. Temperature and Salinity
2. Option D. (I think)
3. Option D.
Hope your test goes well!
8 0
3 years ago
What type of elements are generally involved in covalent bonding?
Roman55 [17]
<span>In organic chemistry, covalent bonding is most often associated with carbon compounds, which are known as organic chemicals. Hydrogen is also involved most of the time, as well as oxygen. Other elements can also be involved, but less frequently.</span>
5 0
3 years ago
Which item has the most thermal energy?
Ksju [112]

Answer:

1L of hot water just below the Boling point

Explanation:

asking questions is best to learn please ask more questions

3 0
3 years ago
Read 2 more answers
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
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