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12345 [234]
3 years ago
12

PLEASE ANSWER ASAP CAUSE THIS QUIZ IS DUE SOON

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:

4x-2y=2

Step-by-step explanation:

Line R is represented by the following equation:

x+y=2

We need to choose another system of equation of x+y=2

whose solution is (1,1)

The equation must be satisfy the point (1,1)

Option 1: 2x+y = 2

Put x=1 and y=1

2(1)+1 = 3

3 ≠ 2

False

Option 2: 4x-2y=2

Put x=1 and y=1

4(1) - 2(1) = 2

2 = 2

True

Option 3: 2x-2y=2

Put x=1 and y=1

2(1) - 2(1) = 0

0 ≠ 2

False

Option 4: x+y=4

Put x=1 and y=1

1+1 = 2

2 ≠ 4

False

Hence, The system of equation is 4x-2y=2

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If x>2,then x2-x-6/x2-4=
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\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)
---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}


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3 years ago
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