Answer:125 TO THE PEOPLE WHO SEE THIS HAVE A GOOD DAY AND STAI SAFE OUT THERE!!!
Step-by-step explanation:
Suppose
is another solution. Then

Substituting these derivatives into the ODE gives


Let
, so that

Then the ODE becomes

and we can condense the left hand side as a derivative of a product,
![\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%3D0)
Integrate both sides with respect to
:
![\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%5C%2C%5Cmathrm%20dx%3DC)

Solve for
:

Solve for
:

So another linearly independent solution is
.
Answer:
Given Polynomial:

Factors of Coefficient of terms
80 = 5 × 16
32 = 2 × 16
48 = 3 × 16
Common factor of the coefficient of all term is 16.
Each term contain variable. So the Minimum power of b is common from all terms.
Common from all variable part comes b².
So, Common factor of the polynomial = 16b²
⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )
⇒ 16b² ( 5b² - 2c³ + 3b²c )
Therefore, Statements that are true about David's word are:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property