All categories

3 years ago

A cube has a lateral surface area of 64sq m find the total surface area of the cube

Mathematics

1 answer:

Roman55 [17]3 years ago

8 0

Answer:

384 square meters.

Step-by-step explanation:

Given that a cube has a lateral surface area of 64 square meters, to find the total surface area of the cube, the following calculation must be performed, knowing that the formula to calculate the area of a cube is to multiply by 6 (the number of sides of the cube) the area of one of its sides:

A x 6 = X

64 x 6 = X

384 = X

Thus, the area of the cube is 384 square meters.

You might be interested in

Drag the point A to the location indicated in each scenario to complete each statement.

Art [367]

The graph from which the position of the point A can determined following

the multiplication with a scalar is attached.

Responses:

If A is in quadrant I and is multiplied by a negative scalar, c, then c·A is in quadrant III

If A is in quadrant II and is multiplied by a positive scalar, c, then c·A is in quadrant II

If A is in quadrant II and is multiplied by a negative scalar, c, then c·A is in quadrant IV

If A is in quadrant III and is multiplied by a negative scalar, c, then c·A is in quadrant I

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, c, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

c·A = c·a + c·b·i is in the quadrant III (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar c, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

c·A = -c·a + c·b·i is in quadrant II

Multiplying A by negative scalar if A is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in quadrant IV

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying A with a negative scalar c gives;

c·A = c·a + c·b·i

c·a is positive

c·b is positive

Therefore;

c·A = c·a + c·b·i is in quadrant I

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0

3 years ago

Which statement is true about ∠1 and ∠2?

gavmur [86]

Answer: Most likely A

Step-by-step explanation:

the reason I say its A is because of the face that congruent means in line not and straight. Though in your answer it shows that they are not alined so that leaves us with complemantary and the 2 complementary answer choices are

A & C but C is wrong because it say alternate which also means the that they would be 2 different angels so yeah I'm gonna go for A.

Good luck :)

5 0

2 years ago

What is the slope of the line shown?

Olin [163]

By using two arbitrary points on the line, we can find the slope using the slope formula:

$\frac{y.2 - y.1}{x.2 - x.1} = m$

We'll use the points (0, 4) and (5, 1) for this.

1 - 4 / 5 - 0

-3 / 5

The slope of the line is -3/5.

4 0

3 years ago

A parking lot has two entrances. Cars arrive at Entrance 1 according to a Poisson Probability Distribution at an average of thre

dusya [7]

Answer:

note:

please find the attached solution

7 0

4 years ago

Solve these simultaneous equations:

ivolga24 [154]

Answer:

1) We have the system:

5*x - 3*y = 15

4*x + 3*y = 6

To solve this, we first need to isolate one of the variables in one of the equations, let's isolate x in the first equation:

x = 15/5 + (3/5)*y = 3 + (3/5)*y

Now we can replace this in the other equation to get:

4*( 3 + (3/5)*y) + 3*y = 6

and solve this for y.

12 + (12/5)*y + 3*y = 6

(12/5 + 3)*y = 6 - 12 = -6

(12/5 + 15/5)*y = -6

(27/5)*y = -6

y = -6*(5/27) = 1.11

Now we can replace this in the equation:

x = 3 + (3/5)*y

To get the value of x.

x = 3 + (3/5)*1.11 = 3.67

Then the solution of this system is the point (3.67, 1.11)

2) Now we have the system:

2*x + 5*y = 26

4*x + 3*y = 24

The solution method is the same as before:

x = 26/2 - (5/2)*y = 13 - (5/2)*y

Now we replace this in the other equation:

4*( 13 - (5/2)*y) + 3*y = 24

52 - 10*y + 3*y = 24

52 - 7*y = 24

52 - 24 = 7*y

28 = 7*y

28/7 = y

4 = y

now we replace this in the equatio:

x = 13 - (5/2)*y

x = 13 - (5/2)*4 = 13 - 10 = 3

The solution of this sytem is (3, 4)

3) Now we have the system:

3*x + 3*y = 39

2*x - 3*y = -2

first we isolate x in the first equation:

x = 39/3 - 3*y/3 = 13 - y

Now we can replace this in the other equation:

2*(13 - y) - 3*y = -2

26 - 2*y - 3*y = -2

26 - 5*y = -2

26 + 2 = 5*y

28 = 5*y

28/5 = y = 5.6

Now we can replace this in the equation:

x = 13 - y

To get the x-value

x = 13 - 5.6 = 7.4

Then the solution for this system is (7.4, 5.6)

4 0

3 years ago