Answer:
- The equation that represent the cost C of renting a car and driving x miles is C = $39.11 + $0.50x
- $130 can travel 181.32 miles
Step-by-step explanation:
From the question, a rental company rents a luxury car at a daily rate of 39.34 $ plus $.50 per mile, that is
$0.50 is added to the initial $39.34 for every mile.
The equation that represent the cost C of renting a car and driving x miles is
C = $39.34 + $0.50x
Now, to determine how many miles 130$ can travel,
we will put C = $100, and determine x in the above equation
$130 = $39.34 + $0.50x
$130 - $39.34 = $0.50x
$90.66 = $0.50x
x = $90.66/$0.50
x = 181.32
Hence, $130 can travel 181.32 miles
Could you zoom out a little maybe? it looks like you cut off something in front of dot
Answer:
I. m = 2401
II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Step-by-step explanation:
I. Determination of m
x ∆ y = x² − 2xy + y²
2 ∆ − 5 = √m
2² − 2(2 × –5) + (–5)² = √m
4 – 2(–10) + 25 = √m
4 + 20 + 25 = √m
49 = √m
Take the square of both side
49² = m
2401 = m
m = 2401
II. Simplify ((n+1) ∆ y)/n
We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:
x ∆ y = x² − 2xy + y²
(n+1) ∆ y = (n+1)² – 2(n+1)y + y²
(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²
(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1
(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1
(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1
(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1
(n+1) ∆ y = (n – y + 2)(n – y) + 1
((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n
((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Answer:
the answer would be 1/15, or approximately 0.067.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Part A: The pancake is a cylinder shape with a circular top and bottom and straight middle.
Part B: Rotating a circle will NOT make a cylinder. Instead rotating a rectangular around a vertical axis will. It is a rectangle of 1cm height and 7cm length rotating around an axis at its edge.**
**Thanks to Moderator wegnerkolmp2741o who pointed out that it has to be a rectangle of 1cm height and 7cm length rotating around an axis at its edge. My original option of 1cm height and 14cm length rotating around its center would cause an overlapping shape.
