The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer:
Step-by-step explanation:
MH is the diameter and it divides the circle in half.
MXH is the arc between the endpoints of the diameter, therefore is semicircle.
Correct choice is C
Answer:
Step-by-step explanation:
18=2×3×3
48=2×2×2×2×3
G.C.F.=2×3=6
18+48=66
6×11=66
Answer:
80 gal
Step-by-step explanation:
20 gal takes her 400 mi
Vol. of gas = 1600 ×20/400
Vol. of gas = 1600 ×1/20
Vol. of gas = 80 gal
Betty will use 80 gal of gas.
