Explanation:
The more reactive element replaces less reactive element during chemical reaction.
Since, potassium is more reactive than beryllium. When potassium reacts with beryllium choride, it replaces beryllium and forms potassium chloride and produces beryllium.
Repeat trials multiple times
<span>0.0687 m
The balanced equation is
BaCl2 + Na2SO4 ==> BaSO4 + 2 NaCl
Looking at the equation, it indicates that there's a 1 to 1 ratio of BaCl2 and Na2SO4 in the reaction. So the number of moles of each will be equal. Now calculate the number of moles of Na2SO4 we had. Start by looking up atomic weights.
Atomic weight sodium = 22.989769
Atomic weight sulfur = 32.065
Atomic weight oxygen = 15.999
Molar mass Na2SO4 = 2 * 22.989769 + 32.065 + 4 * 15.999 = 142.040538 g/mol
Moles Na2SO4 = 0.554 g / 142.040538 g/mol = 0.003900295 mol
Molarity is defined as moles per liter, so let's do the division.
0.003900295 mol / 0.0568 l = 0.068667165 mol/l = 0.068667165 m
Rounding to 3 significant figures gives 0.0687 m</span>
Answer:
<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.
Explanation:
The balanced equation:
1 mole Na3PO4 = 164 g/mole (Molar mass)
1 mole NaOH = 40 g/mole (Molar mass)
Now,
1 mole of Na3PO4 produce = 3 mole of NaOH
164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH
or
120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4
1 g/mol of NaOH is produced from =
100 grams of NaOH is produced from =
gram of Na3PO4
calculate,
= 136.67 g
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