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shusha [124]
3 years ago
13

find the volume of an item using a scale and waterA crown made of alloy of gold and silver has a volume of 60cm3and mass of 1050

g.find mass of gold if density of gold is 19.3g/cm3 while of silver is 10.5g/cm3
Chemistry
1 answer:
KiRa [710]3 years ago
4 0

Answer:

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

Explanation:

Density is defined as mass of the substance present in unit volume of the substance.

Mass of gold in an alloy of crown= m

Mass of silver in an alloy of crown = M

Volume  gold in an alloy of crown= v

Volume of silver in an alloy of crown = V

Density of gold = 19.3 g/cm^3

Density of silver = 10.5 g/cm^3

Volume of the crown = 60 cm^3

60 cm^3=v+V

60 cm^3=\frac{m}{19.3 g/cm^3}+\frac{M}{10.5 g/cm^3}..(1)

Mass of eh crown = 1050 g

1050g =m+M..(2)

Solving equation (1) and (2):

m = 960.61 g

M = 89.39 g

Volume of the gold = v = \frac{960.61 g}{19.3 g/cm^3}=49.77 cm^3

Volume of silver = V = 60 cm^3-v=60 cm63-49.77 cm63=10.23 cm^3

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

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If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?
Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0
3 years ago
Write the balanced chemical equations of the following reaction: Hydrogen and oxygen react to form water.
timofeeve [1]
H2 + O = H2O
Hydrogen is a diatomic molecule and reacts with oxygen to create Water or H2O
4 0
3 years ago
1. A light bulb is filled with 3.54 g of argon at 25 C and 725 mmHg. What is
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Answer: The volume of given gas is 2.27 L.

Explanation:

Given: Mass = 3.54 g

Temperature = 25^{o}C = (25 + 273) K = 298 K

Pressure = 725 mm Hg (1 mm Hg = 0.00131579) = 0.95 atm

As moles is the mass of substance divided by its molar mass.

So, moles of argon (molar mass = 40 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{3.54 g}{40 g/mol}\\= 0.0885 mol

Formula used to calculate the volume of given gas is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times V = 0.0885 mol \times 0.0821 L atm/mol K \times 298 K\\V = 2.27 L

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3 0
3 years ago
Which country has the largest deposit of coal? A. Azerbaijan B. Russia C. Armenia D. Georgia
vazorg [7]

Answer:

The answer is B. Russia

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Rufina [12.5K]

Answer:

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Synthesis: ΔH = 25 kJ - (-30 kJ) = 55 kJ  

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Double Replacement: ΔH = 60 kJ - 10 kJ = 50 kJ

Explanation:

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