All categories

2 years ago

- Level

Mathematics

2 answers:

Sergeeva-Olga [200]2 years ago

6 0

answer it is the 3rd one

Kazeer [188]2 years ago

4 0

2nd is good no cap about it

You might be interested in

Which multiplication problem is represented by the model?

maksim [4K]

0.8 is the answer I hope this helps if you don’t want it decimal form here’s exact from 4/5

6 0

3 years ago

Please answer a and b

Assoli18 [71]

Answer:

(-2,1) (-1,1),(0,1)

Step-by-step explanation:

find the gradient first

6 0

3 years ago

29 less than -10 times a number is equal to -18 times a number +91

sergejj [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

3 years ago

1/2x+5=1/3x what do you multiply the equation by in order to get rid of the fractions in the problem

earnstyle [38]

Answer:

we should multiply by 6 to get rid of the fractions in problem

6 0

2 years ago