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Anestetic [448]

3 years ago

13

A camera phone called the iPhone X has an image sensor size of 5 mm and a focal length of 4 mm. How long of a selfie-stick must

you use to take a picture of you and Liz Cambage of the Las Vegas Aces who stands at 2.032 meters and not be cropped (i.e., the image size can't exceed 5 mm)?

1 answer:

azamat3 years ago

4 0

Answer:

length of selfie-stick is 1.62 m

Explanation:

Given data

image size h1 = 5 mm = 5 × $10^{-3}$ m

focal length = 4 mm = 4 × $10^{-3}$ m

distance h2 = 2.032 m

to find out

How long of a selfie-stick

solution

here we find first magnification

that is M = h1 /h2

M = 5 × $10^{-3}$ / 2.032

M = 2.46 × $10^{-3}$

and we know M = p/q

so p = Mq = 2.46 × $10^{-3}$ q

so we apply lens formula

1/f = 1/p - 1/q

1/ 4 × $10^{-3}$ = 1 / 2.46 × $10^{-3}$ q - 1/q

q = 1.622 m

so length of selfie-stick is 1.62 m

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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh

g100num [7]

To solve this problem we will apply trigonometric and optical concepts that allow us to obtain the minimum distance required. The resolution of the eye is given under the following condition,

$\theta = \frac{1.22\lambda}{D}$

Here,

$\lambda = Wavelength$

$D = Diameter$

With the values we have that the diameter will be,

$\theta = \frac{1.22(534nm)}{5.37mm}$

$\theta = 1.213*10^{-4}$

The relation between the distance of the lights and the distance from the eye to the lamp is given under the function,

$sin\theta = \frac{d}{L}$

For small angles $sin\theta = \theta$ , then

$\theta = \frac{d}{L}$

Here,

d = Distance between lights

L = Distance from eye to lamp

$1.213*10^{-4} = \frac{0.673m}{L}$

$L = \frac{0.673m}{1.213*10^{-4}}$

$L = 5548.22m$

Therefore the distance will be 5.5km

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3 years ago

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kirill115 [55]

The answer is D

Explanation:

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7 0

3 years ago

How much force is needed to accelerate a 62 kg skier at 3 m/sec2?

Fittoniya [83]

Answer:

<h2>The answer is 186 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 62 kg

acceleration = 3 m/s²

We have the final answer as

force = 62 × 3

We have the final answer as

<h3>186 N</h3>

Hope this helps you

8 0

3 years ago

You push your couch a distance of 3.9 m across the living room floor with a horizontal force of 220.0 n. the force of friction i

Mrac [35]

The general formula to calculate the work is:

$W=Fd \cos \theta$

where F is the force, d is the displacement of the couch, and $\theta$ is the angle between the direction of the force and the displacement. Let's apply this formula to the different parts of the problem.

(a) Work done by you: in this case, the force applied is parallel to the displacement of the couch, so $\theta=0^{\circ}$ and $\cos \theta=1$ , therefore the work is just equal to the product between the horizontal force you apply to push the couch and the distance the couch has been moved:

$W=Fd=(220.0 N)(3.9 m)=858 J$

(b) work done by the frictional force: the frictional force has opposite direction to the displacement, therefore $\theta=180^{\circ}$ and $\cos \theta=-1$ . Therefore, we must include a negative sign when we calculate the work done by the frictional force:

$W=-Fd=-(144.0 N)(3.9 m)=-561.6 J$

(c) The work done by gravity is zero. In fact, gravity (which points downwards) is perpendicular to the displacement of the couch (which is horizontal), therefore $\theta=90^{\circ}$ and $\cos \theta=0$ : this means

$W=0$ .

(d) Work done by the net force:

The net force is the difference between the horizontal force applied by you and the frictional force:

$F=220 N-144 N=76 N$

And the net force is in the same direction of the displacement, so $\theta=0^{\circ}$ and $\cos \theta=1$ and the work done is

$W=Fd=(76 N)(3.9 m)=296.4 J$

4 0

3 years ago

An object is traveling at a constant velocity of 10m/s for 4 seconds. What is its acceleration?

saw5 [17]

Answer:

<h2>The answer is 2.5 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula

$acceleration = \frac{velocity}{time} \\$

From the question

time = 4 s

velocity = 10 m/s

So we have

$acceleration = \frac{10}{4} = \frac{5}{2} \\$

We have the final answer as

<h3>2.5 m/s²</h3>

Hope this helps you

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4 years ago