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2 years ago

2х + 3y = -6 —4х – бу = 12

Mathematics

1 answer:

Reil [10]2 years ago

8 0

Answer:

2x+3y-6=2...........??

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How many combinations of 6 students can a teacher choose from 30 students?

neonofarm [45]

Answer: 593775

Step-by-step explanation: 30C6 =30x29x28x27x26x25 / 6x5x4x3x2x1 =593775

6 0

2 years ago

what algorithm (rule) will produce the correct result for the sum "a+b" where a and b each represent any rational number.

Leokris [45]

Answer:

To find the sum of a + b where a and b are rational number.

1. when a and b are natural numbers

just add them . for example a =3, b=8

then ,a + b = 11

2. When a and b are whole numbers,

simply add them . for example a= 0, b=8

a+ b = 0 + 8= 8

3. When a and b are integers

for example, a =-1 b=8,

a+ b= -1+ 8 =7,

a=-2, b= -8

a+ b= -2-8=-10

a= -6 , b=2

a+ b= -6 + 2= -4

a= 8, b= -2

a+ b= 8 +(-2) =6

I have written this because Rational number = [Integers{Whole number(Natural number)}]

now when a= Any fraction= $\frac{p}{q}$ and b = Any fraction= $\frac{u}{v}$

now ,

$\frac{p}{q} + \frac{u}{v}$

Find L.C.M of q and v

= if q and v are Co-prime , just multiply them to find their L.C.M.

For example 14,9. LCM=14×9=126

Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example

q=12 and v=18

12 =2×2×3

18=2×3×3

common factor =2,3

non common=2,3

L.C.M= 2×2×3×3=36

Suppose LCM of q and v = r

then , $\frac{p}{q} + \frac{u}{v}$

= $\frac{{\frac{r}{q}}\times p+{\frac{r}{v}\times u}}{r}\\$

= ${{\frac{r}{q}}\times p+{\frac{r}{v}\times u}} = k$

then ,

a + b= $\frac{k}{r}$

5 0

2 years ago

Whatwould u times by 9 to get 99?

Aleonysh [2.5K]

The answer would be 11.

6 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

1 year ago

Isosceles JAM has convex angle M. JM=35,MA=4n+3, angle J=14w-1, and angle m=98 Find n. Find w. Find the perimeter of JAM

Lena [83]

Answer:

n = 8, w = 3 and perimeter = 122.83 units.

Step-by-step explanation:

Let the angle M is the angle between the equal sides of isosceles JAM.

So, JM = MA

⇒ 35 = 4n + 3

⇒ 4n = 32

⇒ n = 8 (Answer)

Now, if ∠ J = 14w - 1 and ∠ M = 98°, then

2(14w - 1) + 98 = 180

⇒ 2(14w - 1) = 82

⇒ 14w - 1 = 41

⇒ w = 3 (Answer)

Now, draw a perpendicular bisector on JA from vertex M and it meets JA at P say.

So, Δ MPJ will be a right triangle with ∠ J = (14w - 1) = 41° {Since w = 3}

Hence, $\cos 41 = \frac{JP}{JM} = \frac{JP}{35}$

⇒ JP = 35 cos 41 = 26.415

So, JA = 2 × JP = 52.83

So, the perimeter of Δ JAM is = 35 × 2 + 52.83 = 122.83 units (Answer)

4 0

3 years ago