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masha68 [24]
3 years ago
8

Look at this pattern: 1,4,9,16,__,__,__,.....

Mathematics
1 answer:
noname [10]3 years ago
5 0

Answer:

1,4,9,16,25,36,49

Step-by-step explanation:

The pattern is :

1,4,9,16,_,_,_,...

First no is 1

Second no is 4

Third no is 9

Fourth no is 16

Difference between second and first no. = 4-1 = 3

Difference between third and second no. = 9-4= 5

Difference between fourth and third no. = 16-9 = 7

Fifth no is :

16 + 9 = 25

Sixth no is : 25 + 11 = 36

Secenth no. is : 36 + 13 = 49

Hence, the pattern is :

1,4,9,16,25,36,49

You might be interested in
The length of a rectangular field is 6 feet less than 5 times its width.
nordsb [41]

Answer:

5X-6)+(5X-6)+X+X=252 , now lets add all the X together, and then add the whole numbers.

12X-12=252 , now lets work this by adding 12 on each side of the equation:

12X-12+12=252+12

12X=264 , divide both sides by 12.

X=22

Now lets prove X =22:

(5·22–6)+(5·22–6)+22+22=252

(110–6)+(110–6)+22+22=252

104+104+44=252

208+44=252

252=252Therefore the length is 104 feet each and the width is 22 feet each.

7 0
3 years ago
Round off 2371 +1625 to the nearest hundred​
riadik2000 [5.3K]

Answer:

2000 + 2000 = 4000

Step-by-step explanation:

2371 is rounded to 2000

1625 is rounded to 2000

2000 + 2000 = 4000

Hope this helps!

6 0
3 years ago
Read 2 more answers
Can someone please help me with this question?
Anna007 [38]
X = 28 hope this helps
3 0
3 years ago
Find the slope given the graph below:
RoseWind [281]

Answer:

5/3

Step-by-step explanation:

rise over run

(y2-y1)/(x2-x1)

(-2-3)=-5

(-2-1)=-3

6 0
3 years ago
Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
Aleonysh [2.5K]

Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

5 0
4 years ago
Read 2 more answers
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