Answer:
127 pages
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
The ratio of the area of the similar triangles is equal to the square of the side of the corresponding sides
Suppose the corresponding side on figure A is 
On solving
![\Rightarrow \dfrac{16}{49}=[\dfrac{x}{5}]^2\\\\\Rightarrow \dfrac{x}{5}=\sqrt{\dfrac{16}{49}}\\\\\Rightarrow \dfrac{x}{5}=\dfrac{4}{7}\\\\\Rightarrow x=\dfrac{20}{7}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B16%7D%7B49%7D%3D%5B%5Cdfrac%7Bx%7D%7B5%7D%5D%5E2%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7Bx%7D%7B5%7D%3D%5Csqrt%7B%5Cdfrac%7B16%7D%7B49%7D%7D%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7Bx%7D%7B5%7D%3D%5Cdfrac%7B4%7D%7B7%7D%5C%5C%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B20%7D%7B7%7D)
The triangle's height would have to be 2 times that of the rectangles. To know this, you canlook at the formulas for the Area of each shape.
Rectangle: bh
Triangle: bh/2
A triangle is just a rectangle cut in half. In order for the areas to be the same asleep as the bases, the only way it can be true is if the height were 2 times larger than the height of the rectangle.