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sergey [27]
3 years ago
12

Which of these is not an example of

Physics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

A) The process that give us day  and night.

Explanation:

From the answer choices provided the one that is not an example of this is the process that give us day  and night. This is because, the day/night cycle occurs as the Earth spins on it's axis. This cause one side of the Earth to be facing the Sun, which is the side that is currently experiencing day time while the other side is experiencing night time. As the Earth spins the cycles repeat. This is not an example of revolving.

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Serving at a speed of 170 km/h, a tennis player hits the ball at a height of 2.5 m and an angle θ below the horizontal. the base
Sholpan [36]

serving speed = 170 km/h

now we will convert it into m/s

v = 47.22 m/s

now it will have two components along x and y directions

v_x^2 + v_y^2 = 47.22^2

also in x and y directions we know

2.5 - 0.91 = v_y*t + \frac{1}{2}gt^2

11.9 = v_x *t

1.59 = v_y*t + 4.9*t^2

1.59 = 11.9 tan\theta + 4.9*(\frac{11.9}{47.22})^2(1 + tan^2\theta)

1.59 = 11.9 tan\theta + 0.311 (1 + tan^2\theta)

by solving above equation we have

tan\theta = 0.107

\theta = 6.11 degree

so angle is 6.11 degree below the horizontal

now we have

v_y = 47.22 sin6.11 = 5.02 m/s

v_x = 47.22 cos6.11 = 46.95 m/s

now time taken by ball to reach the ground will be

2.5 = 5.02 * t + \frac{1}{2}gt^2

t = 0.37 s

now the displacement in x direction will be

x = v_x * t

x = 46.95 * 0.37 = 17.37 m

now the distance from net will be

d = 17.37 - 11.9 = 5.47 m

So it will land inside the line

3 0
3 years ago
Calculate the amount of gravitational potential energy at the top of each hill
Marizza181 [45]
The gravitational potential energy has the formula:
PE = mgh
where PE is in joules
m is the mass of the object in kg
g is the acceleration due to gravity
h is the height in m

since you did not give the value of h, i cannot fully answer your quesstion.
PE = (58/1000 kg) (9.81m/s2) h
PE = 0.57h
just substitute the value of h in the equation
5 0
4 years ago
Through which of these media do sound waves
defon
Wood i think could be wrong
3 0
3 years ago
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
4 years ago
The voltage in a battery is 9 volts. The resistance is 3 ohms. What is the current? USE CORRECT UNITS!
chubhunter [2.5K]

Answer: Lol “USE CORRECT UNITS!” I GOT YOU BABES: 9/3=3 current is 3 amperes.

Explanation:

3 0
3 years ago
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