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sergey [27]
3 years ago
12

Which of these is not an example of

Physics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

A) The process that give us day  and night.

Explanation:

From the answer choices provided the one that is not an example of this is the process that give us day  and night. This is because, the day/night cycle occurs as the Earth spins on it's axis. This cause one side of the Earth to be facing the Sun, which is the side that is currently experiencing day time while the other side is experiencing night time. As the Earth spins the cycles repeat. This is not an example of revolving.

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Discuss the pros and cons of fission and fusion reactions.
Jet001 [13]

<u>Fission</u>: -

<u>Pros</u>:

- "It does not contribute to the air pollutants in the environment."

- "It does not need costly energy fuels."

- "It is capable of providing energy for 2 to 3 years."

- "It does not make global warming worse."

- "It produces a nuclear reaction that is important."

- "It helps with the field of astronomy."

<u>Cons</u>:

- "It can harm the environment in a way that it disposes waste."

- "It poses a risk to public health."

- "It can cause deadly and costly accidents."

- "It has the potential to open the door for terrorists to create powerful weapons."

<u>Fusion Reactions</u>: -

<u>Pros</u>:

- "Clean energy ."

- "Virtually limitless fuel available ."

- "No chain reaction. Easier to control or stop than fission ."

- "Nuclear fission is either a nuclear reaction or a radioactive decay process in which the nucleus of an atom splits into smaller parts (lighter nuclei) ."

- "Little or no nuclear waste. Core remains radioactive for only 100 years. Possibly radioactive structural elements ."

- "Very low fuel cost."

<u>Cons</u>:

- "Unproven (it will take another years of research to explore it on commercial scale) ."

- "Commercial power plants will be very expensive to build ."

- "Requires extremely high temperatures .

If cold fusion could be achieved, it would be much easier to implement."

8 0
3 years ago
A metal ball has a mass of 2kg and a volume of 6 m3. What is its density
Lena [83]

Answer: The answer is 333.3333 repeating

Explanation:

Divide the mass by the volume.

8 0
2 years ago
Read 2 more answers
What time that take if wavelength 1/10^8 and 3*10^8 m/s?
asambeis [7]

Answer:3.33x10^(-17)

Explanation:

Period=wavelength ➗ velocity

Period=1/10^8 ➗ (3x10^8)

Period=3.33x10^(-17)

5 0
3 years ago
the mass of a large car is 1000 kg. how much force would be required to accelerate the car at a rate of 3 m/sec²​
jek_recluse [69]

Answer:

3000  N

Explanation:

<em>Newton's second law of motion</em> describes the relationship between an object's mass and the amount of force needed to accelerate it.  

This law can be expresses as F=ma,

where  

  • F -  force acting on an object
  • m-  the mass of an object  
  • a -  its acceleration

The more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration.

<em>F = ma</em>

<em>F = 1000×3 </em>

<em>   = 3000  N</em>

5 0
3 years ago
2. An archer shoots an arrow at 83.0 m/s at a 62.0 degree angle. If the ground is flat, how much time is the arrow in the air?
UkoKoshka [18]

Answer:

<em>t=14.96 sec</em>

Explanation:

<u>Diagonal Launch </u>

It's a physical event that happens where an object is thrown in free air (no friction) forming an angle with the horizontal reference. The object then describes a path called a parabola.

The object will reach its maximum height and then return to the height from which it was launched. The equation for the height is :

\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}

Where vo is the initial speed, \theta is the angle, t is the time and g is the acceleration of gravity .

In this problem we'll assume the arrow was launched from the ground level (won't consider the archer's height). Thus y_o=0, and:

\displaystyle y=v_osin\theta \ t-\frac{gt^2}{2}

The value of y is zero twice: when t=0 (at launching time) and in t=t_f when it goes back to the ground. We need to find that time t_f by making y=0

\displaystyle 0=v_osin\theta\ t_f-\frac{gt_f^2}{2}

Dividing by t_f

\displaystyle v_osin\theta=\frac{gt_f}{2}

Then we find the total flight time as

\displaystyle t_f=\frac{2v_osin\theta}{g}

\displaystyle t_f=\frac{2(83)sin\ 62^o}{9.8}

\displaystyle t_f=14.96\ sec

5 0
3 years ago
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