gravitational force between two objects is given as
F = G m₁ m₂/r²
where m₁ = mass of first object , m₂ = mass of second object , r = distance between the two objects .
Initial case :
m₁ = m₂ = m
gravitational force between the objects is given as
F = G m²/r²
Final Case :
m₁ = m₂ = 3 m
new gravitational force between the objects is given as
F' = G (3m)²/r²
F' = 9 G m²/r²
F' = 9 F
hence the gravitational force between the two objects becomes 9 times.
(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and
is the variation of height. Substituting the numbers into the formula, we find

(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.
(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

Answer:
d
Explanation:
According to me answer is d but gas expand more than others
The answer is Alternating Current
Answer:
497.00977 N
3742514.97005
Explanation:
= Density of water = 1000 kg/m³
C = Drag coefficient = 0.09
v = Velocity of dolphin = 7.5 m/s
r = Radius of bottlenose dolphin = 0.5/2 = 0.25 m
A = Area
Drag force

The drag force on the dolphin's nose is 497.00977 N
at 20°C
= Dynamic viscosity = 
Reynold's Number

The Reynolds number is 3742514.97005