What is larger0.04 or 0.2

George wrote an integer. The opposite of George's integer is - 53. Which of these statements about George's integer must be true

Readme [11.4K]

Answer:

D I and IV

Step-by-step explanation:

The opposite of an integer "x" is "-x".

I. The integer is 53. → Since the opposite of George's integer is -53, the integer is -(-53) = 53

II. The integer has an absolute value of - 53. → The absolute value of 53 is 53.

III. The integer is - 53. → It was 53, found in I.

IV. The integer has an absolute value of 53. → It has an absolute value of 53, found in II.

8 0

2 years ago

7. Given f(x) = 6(1 - x) +11, what is the value of f(8) ?

enot [183]

Answer:

f(8)=-31

Step-by-step explanation:

since 8 replaces x in f(x), x should be substituted as 8 in the expression. From there, after you substitute, it becomes 6(1-8)+11. Simplifying that expression is now 6(-7)+11. Multiply 6 and -7, you get -42. -42+11=-31. I hope this helps :)

6 0

2 years ago

Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the

fiasKO [112]

Answer:

a) NORM.S.INV(0.975)

Step-by-step explanation:

1) Some definitions

The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.

NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"

The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.

2) Solution for the problem

Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".

We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.

So for this case the correct function to use is: NORM.S.INV(0.975)

And the result after use this function is 1.96. And we can check the answer if we look the picture attached.