Question

Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a normal force of 8500N

Answer 1

Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

Weight is 8500 N

And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force