Answer:
1) t = 3.45 s, 2) x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s
,
5) θ = -40.2º
Explanation:
This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.
1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff
y = y₀ + 
t - ½ g t²
When leaving the cliff the speed is horizontal v_{oy}= 0 and at the bottom of the cliff y = 0
0 = y₀ - ½ g t2
t = √ 2y₀ / g
t = √ (2 60 / 9.8)
t = 3.45 s
2) The horizontal distance traveled
x = v₀ₓ t
x = 40 3.45
x = 138 m
3) The vertical velocity at the point of impact
v_{y} = I go - g t
v_{y} = 0 - 9.8 3.45
v_{y} = -33.81 m /s
the negative sign indicates that the speed is down
4) the resulting velocity at this point
v = √ (vₓ² + v_{y}²)
v = √ (40² + 33.8²)
v = 52.37 m / s
5) angle of impact
tan θ = v_{y} / vx
θ = tan⁻¹ v_{y} / vx
θ = tan⁻¹ (-33.81 / 40)
θ = -40.2º
6) sin (-40.2) = -0.6455
7) tan (-40.2) = -0.845
8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis
The answer from the given options is "A. Creep".
Alternate freezing and thawing often leads to "creep".
Creep refers to the low mass development of soil and soil material down slants, driven fundamentally by gravity yet facilitated by immersion with water and by substitute freezing and thawing. Generally not distinguishable with the exception of through expanded perception.
The initial velocity of the ball is 8.2 m/s
Explanation:
The motion of the ball is a projectile motion, which consists of two separate motions:
- A uniform motion along the horizontal direction, at constant velocity
- A uniformly accelerated motion along the vertical direction, with constant acceleration (
, acceleration of gravity)
The range of a projectile can be derived by the equation of motions along the two directions, and it is found to be:
where
v is the initial velocity of the projectile
is the angle of projection
g is the acceleration of gravity
For the ball in this problem, we have
d = 6 m is the range
Solving for v, we find the initial velocity:
Learn more about projectile motion:
brainly.com/question/8751410
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Answer:
the riders must be greater than friction and the force of gravity. uh I guessed
Because the heat of the fire diffuses into the atmosphere and then we absorb it into our body
