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ankoles [38]
4 years ago
15

How many liters would be equal to 14 milliliters

Physics
1 answer:
natita [175]4 years ago
7 0
0.014 liters = 14 milliliters.
Hope it helps!
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Does a business day include the day you ordered it?
Daniel [21]
Depends, but generally, it does not include the day the order was placed.
6 0
4 years ago
Read 2 more answers
The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to
irina1246 [14]

Answer:

F = 10.86 units

Explanation:

The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:

F = √(Fₓ² + Fy²)

where,

F = Magnitude of the Vector = ?

Fₓ = magnitude of the x-component of vector = 8.7 units

Fy = magnitude of y component of vector = - 6.5 units

Therefore, using these values in the equation, we get:

F = √[(8.7 units)² + (- 6.5 units)²]

F = √(117.94 units²)

<u>F = 10.86 units</u>

5 0
3 years ago
State a hypothesis about what might happen as you proceed through the lab.
Kamila [148]

A hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.

<h3>What is a hypothesis?</h3>

A hypothesis is a given explanation of a particular scientific question emerged by observing the real world.

Hypotheses are explanations that must be tested (either confirmed or rejected) by using the scientific method.

In conclusion, a hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.

Learn more about lab hypothesis here:

brainly.com/question/11555274

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6 0
3 years ago
A typical AA size rechargeable NiMH battery can store 1100-2100 mAh of electric charge. The small print on the battery in your h
Anni [7]

Answer:

The electric charge, q (in coulomb units) = 5004 C  

Given:

The charge stored as printed on NiMH battery, q = 1390 mAh  

Solution:

To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:

1 mA = 1\times 10^{-3}

1 hour = 60\times 60 = 3600 s

Also, we know that the rate of flow of charge is electric current, I:

I = \frac{q}{t}

⇒ q = [tex]I\times t[tex]                                   (1)

where

q = electric charge

I = current

t = time taken for flow of current

Using eqn(1), we get:

q = [tex]1390\times 10^{-3}\times 60\times 60[tex]

q = 5004 A-s = 5004 C

8 0
3 years ago
An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o
kondor19780726 [428]

Answer:

2.56 m/s²

Explanation:

A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.

f = 1/2l√(T/μ)

where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s

f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²

m₁g = 4l²μ/T²

g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²

g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²

4 0
3 years ago
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