Depends, but generally, it does not include the day the order was placed.
Answer:
F = 10.86 units
Explanation:
The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:
F = √(Fₓ² + Fy²)
where,
F = Magnitude of the Vector = ?
Fₓ = magnitude of the x-component of vector = 8.7 units
Fy = magnitude of y component of vector = - 6.5 units
Therefore, using these values in the equation, we get:
F = √[(8.7 units)² + (- 6.5 units)²]
F = √(117.94 units²)
<u>F = 10.86 units</u>
A hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.
<h3>What is a hypothesis?</h3>
A hypothesis is a given explanation of a particular scientific question emerged by observing the real world.
Hypotheses are explanations that must be tested (either confirmed or rejected) by using the scientific method.
In conclusion, a hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.
Learn more about lab hypothesis here:
brainly.com/question/11555274
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Answer:
The electric charge, q (in coulomb units) = 5004 C
Given:
The charge stored as printed on NiMH battery, q = 1390 mAh
Solution:
To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:
1 mA = 
1 hour = 
Also, we know that the rate of flow of charge is electric current, I:
I = 
⇒ q = [tex]I\times t[tex] (1)
where
q = electric charge
I = current
t = time taken for flow of current
Using eqn(1), we get:
q = [tex]1390\times 10^{-3}\times 60\times 60[tex]
q = 5004 A-s = 5004 C
Answer:
2.56 m/s²
Explanation:
A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.
f = 1/2l√(T/μ)
where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s
f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²
m₁g = 4l²μ/T²
g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²
g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²