Answer:
(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.
Explanation:
Given that,
a ball is spun around in circular motion such that it completes 50 rotations in 25 s.
(1). Let T be the period of its rotation. It can be calculated as follows :

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

Hence, this is the required solution.
Answer:
Temperature at the exit = 
Explanation:
For the steady energy flow through a control volume, the power output is given as

Inlet area of the turbine = 
To find the mass flow rate, we can apply the ideal gas laws to estimate the specific volume, from there we can get the mass flow rate.
Assuming Argon behaves as an Ideal gas, we have the specific volume 
as


for Ideal gasses, the enthalpy change can be calculated using the formula

hence we have


<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>
evaluating the above equation, we have 
Hence, the temperature at the exit = 
Answer:
The ladder is 3.014 m tall.
Explanation:
To solve this problem, we must use the following formula:
v = x/t
where v represents the woman’s velocity, x represents the distance she climbed (the height of the ladder), and t represents the time it took her to move this distance
If we plug in the values we are given for the problem, we get:
v = x/t
2.20 = x/1.37
To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:
x = (2.20 * 1.37)
x = 3.014 m
Therefore, the ladder is 3.014 m tall.
Hope this helps!
Answer:
714.285s
Explanation:
use relative velocity
8-4.5 = 3.5m/s
x = 2500m
2500/3.5 = 714.285s = 700s (with sig figs)
Answer:
...
Explanation:
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