Answer:
By induction method
Explanation:
Induction method involves charging an electrically neutral body by bringing it in contact with an electrically charged body.
For the electrophus, a charge opposite that on the slab is induced on the side in contact with the slab; driving the opposite charge (this will be the same as that on the slab) to the other end of the elctrophus. Touching the electrophus removes the charge opposite the charge induced on the electrophus by the charged slab either by drawing up charge from the earth or taking the charge to earth (depends on the charge. A negative charge is drawn to earth while a positive charge draws up electrons from the earth)
Because of the axis of the earth. It takes 24 hours to rotate 360 degrees.
Answer:
The hill should be not less than 0.625 m high
Explanation:
This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that
is constant, being U the potential energy and K the kinetic energy
When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
We can solve for h:
The hill should be not less than 0.625 m high
Answer:
speed and acceleration of the turbine V = 80.24 m/s and a = 109.1 m/s²
Explanation:
The wind turbine describes a circular motion, with constant angular velocity, we can find the speed with the equation
V = x / t
Where x is the distance traveled which is the length of the circle (X = 2πr) and time is the time in a revolution, which in this case is called the period
t = 60/13
t = 4.62 s
x = 2 p1 59
x = 370.71 m
V = 370.1 / 4.62
V = 80.24 m / s
The centripetal acceleration is given by the equation
a = V² / r
a = 80.24²/59
a = 109.1 m / s²
The second part of the exercise seems totally independent
The dog r = 16cm with a speed of 2.5 m/s, ask us the centripetal force
F = m a
F = m (v² / r)
m = 10 mg (1g / 1000mg) 1 Kg / 1000 g) = 1 10⁻⁵ Kg
r = 16 cm (1m / 100cm) = 16 10⁻² m
F = 1 10⁻⁵ 2.5²/16 10⁻²
F = 3.91 10⁻² N
Let's calculate the relationship between the force and the weight of the drop
F / W = 3.91 10⁻² (1 10⁻⁵ 9.8)
F / W = 3.99 10
²
See that the force of the shake is approximately 400 times greater than the weight of the drop
