Answer:
P₁ = 219.3 Pa
Explanation:
This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.
Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.
P₁ = P₂
pressure is defined by
P = F / A
we subtitute
F₁ / A₁ = F₂ / A₂
F₁ = F₂ A₁ / A₂
the area in a circle is
A = π r² = π d² / 4
we substitute
F₁ = F₂ (d₁ / d₂)²
we calculate
F₁ = 17640 (2/32)²
F₁ = 68.9 N
Having the force to be applied we can find the air pressure on the small plunger
P₁ = F₁ / A₁
P₁ = F₁ 4 / π d₁²
let's calculate
P₁ = 68.9 4 / (π 0.02²)
P₁ = 219.3 Pa
Answer:
Explanation:
Because of the following ,it is useful to select both objects as the system during collision between an electron and a hydrogen atom
1. The total momentum of the system does not change during the collision.
2.The forces the objects exert on each other are internal to the system and don't change the total momentum of the system.
3. During the time interval just before to just after the collision, external forces are negligible.
There will be no way that to happen aton is a positive charge
Together as one moving package, their mass is (15 + 50) = 65 kg.
Kinetic energy = (1/2) (mass) (speed)²
= (1/2) (65 kg) (5 m/s)²
= (32.5 kg) (25 m²/s²)
= 812.5 kg-m²/s² = 812.5 joules .