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3 years ago

Explain how the readings on both meters change when the environmental conditions change.

Physics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

* Temperature changes

* Changes in the tension

* Errors in the meter marks

Explanation:

When we are using several meters to make a measurement we have several aspects that can cause the readings to differ.

* Temperature changes make the dilation between readings different, at higher temperatures the material of the meter expands and the reading decreases.

* Changes in the tension with which the meter is pulled to keep it straight, in general all materials bend under the action of gravity, so you have to pull them to make them straight, if the forces are different from the material is lengthened decide Young's modulus, inducing different readings

* Errors in the meter marks, especially in the initial part that is covered by a hook, different positions of the hook change the readings.

* Structural problems, such as rust, bends that create changes in the length of the meter material.

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A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m

Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force $F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k$

Mass of object = 2.00 kg

Initial position $d=(2.75)i-(2.00)j+(5.00)k$

Final position $d=-(5.00)i+(4.50)j+(7.00)k$

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

$W=F\cdot d$

$W=F\cdot(d_{f}-d_{i})$

Put the value into the formula

$W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)$

$W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)$

$W=2.75\times-7.75+7.50\times6.50+6.75\times2.00$

$W=40.93\ J$

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

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3 years ago

In simple harmonic motion, the speed is greatest at that point in the cycle whenA) the magnitude of the acceleration is a maximu

hram777 [196]

Answer:

C) the magnitude of the acceleration is a minimum.

Explanation:

As we know that ,the general equation of the simple harmonic motion given as

The displacement x given as

x=X sinω t

Then the velocity v will become

v= X ω cosωt

The acceleration a

a= - X ω² sinω t

The speed of the particle will be maximum when cosωt will become 1 unit.

It means that sinωt will become zero.So acceleration and displacement will be minimum.

Therefore when speed is maximum then acceleration will be minimum.

At the mean position the speed of the particle is maximum that is why kinetic energy also will be maximum and the potential energy will be minimum.

Therefore option C is correct.

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3 years ago

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Maslowich

A scientific theory is different from a hypothesis because a theory is a educated guess that is being worked on and proven correct and a hypothesis is a educated guess it is a guess that needs to be proven.

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4 years ago

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taurus [48]

Answer:

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