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3 years ago

Explain how the readings on both meters change when the environmental conditions change.

Physics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

* Temperature changes

* Changes in the tension

* Errors in the meter marks

Explanation:

When we are using several meters to make a measurement we have several aspects that can cause the readings to differ.

* Temperature changes make the dilation between readings different, at higher temperatures the material of the meter expands and the reading decreases.

* Changes in the tension with which the meter is pulled to keep it straight, in general all materials bend under the action of gravity, so you have to pull them to make them straight, if the forces are different from the material is lengthened decide Young's modulus, inducing different readings

* Errors in the meter marks, especially in the initial part that is covered by a hook, different positions of the hook change the readings.

* Structural problems, such as rust, bends that create changes in the length of the meter material.

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I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

$a_y$ = Acceleration in y axis = $9.81\ \text{m/s}^2$

$u_y$ = Initial velocity in y axis = 0

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$

Resultant velocity is given by

$v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}$

The fish is moving at a velocity of 28.1 m/s when it hits the water.

6 0

3 years ago

Cheryl is riding on the edge of a merry-go-round, 2m from the center, which is rotating with an increasing angular speed. Cheryl

WINSTONCH [101]

In circular motion we know that there is two type of acceleration that Cheryl experience

1. Tangential acceleration

2. Centripetal acceleration

here given that

$a_t = 3 m/s^2$

for centripetal acceleration we know that

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{2} = 8 m/s^2$

now we know that both centripetal acceleration and tangential acceleration is perpendicular to each other

so total acceleration is vector sum of both and given as

$a_{net} = \sqrt{8^2 + 3^2} = 8.54 m/s^2$

so total acceleration is 8.54 m/s^2

8 0

3 years ago

Which is the best reason a writer would use a unreliable narrator

avanturin [10]

Answer: Explanation:

Authors sometimes use an Unreliable Narrator to tell the story, a protagonist who can't be trusted to tell the events accurately. Either they are insane, evil, delusional, forgetful, or just plain wrong... whatever their reasons, the writer uses this technique to 'hook' the reader.

7 0

3 years ago

Five equal negative charges are uniformly spaced in a semicircular

balu736 [363]

Answer:

The direction is that of a 3rd quadrant angle

Explanation:

when you have 2 45 angles it equals to 90 then with the 90 we multiply by 2 due to the 2 adjacent angles equating to 180 which swings it to the 3rd quadrant angle

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3 years ago

Alternating Current In Europe, the voltage of the alternating current coming through an electrical outlet can be modeled by the

stealth61 [152]

Answer:

$\frac{50}{\pi }$ Hz

Explanation:

In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;

V(t) = V sin (ωt + Ф) -----------------(i)

Where;

V = amplitude value of the voltage

ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]

Ф = phase difference between voltage and current.

Now,

From the question,

V(t) = 230 sin (100t) ---------------(ii)

By comparing equations (i) and (ii) the following holds;

V = 230

ω = 100

Ф = 0

But;

ω = 2 π f = 100

2 π f = 100 [divide both sides by 2]

π f = 50

f = $\frac{50}{\pi }$ Hz

Therefore, the frequency of the voltage is $\frac{50}{\pi }$ Hz

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3 years ago