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2 years ago

Find a number halfway between 2 1/2 and 1 1/3

Mathematics

1 answer:

kvasek [131]2 years ago

4 0

Answer:

23/12

Step-by-step explanation:

2 1/2 = 5/2(3/3) = 15/6

1 1/3 = 4/3(2/2) = 8/6

15/6 - 8/6 = 7/6

7/6(1/2) = 7/12

16/12 + 7/12 = 23/12

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Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

4 0

2 years ago

PLZ HURRY IT'S URGENT!!!

mr Goodwill [35]

Answer:

25 two point shots

25 three point shots

2x+3y<100 is that the one missing the sign?

Step-by-step explanation:

25*2=50

25*3= 75

50+75= 125

2x+3y has to be over 100 points

so 2x+3y<100

8 0

2 years ago

In Marta's class, the ratio of students who ate tacos for lunch to the students who ate burritos was 12:18.

boyakko [2]

Answer:

20 30

Step-by-step explanation:

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3 0

2 years ago

Simplify the following radicals. 1. √16 2. √17 3. √18 4. √19 5. √20

Pavel [41]

Answer:

Step-by-step explanation:

$1) \sqrt{16}= \sqrt{4*4}=4\\\\\\2) \sqrt{17}$

This is the simplest form as 17 is a prime number.

$3) \sqrt{18}= \sqrt{2*3*3} = 3 \sqrt{2}\\\\\\4) \sqrt{19}$

19 is a prime number. so it is the simplest form.

$5) \sqrt{20}= \sqrt{2*2*5}=2 \sqrt{5}$

3 0

2 years ago

Hurry. . . . will mark brainliest

11Alexandr11 [23.1K]

Answer:The quote”During the trip they had to fight off seven black men who tried to rob and kill them.Another quote that states this is”He subsequently worked as a hired hand, a surveyor, and a local postmaster. Tells straight off the bat how he was a self made man.

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2 years ago