Given:
The bases of trapezoid measuring 4 m and 12 m.
To find:
The median of the trapezoid.
Solution:
The median of the trapezoid is the average of its bases.

The bases of trapezoid measuring 4 m and 12 m. So, the median of the trapezoid is:



Therefore, the correct option is C.
The absolute change is the difference: 6.88 - 7.25 = -0.37
The rate of change is that divided by the originalprice x 100
Ratre of change: (-0.37/7.25 )*100 = -4.93%
Answer:
I would divide 50 by 4 (Because there are usually 4 weather conditions in game) and whichever the number is closest to it would pick that weather condition
Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time


=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V


h=3m,
dV/dt=25cm/min=0.25 m/min

=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.