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3 years ago

An atom contains 22 protons and 26 neutrons. What is its mass number?

Chemistry

1 answer:

Olin [163]3 years ago

7 0

Answer:

47.867

Explanation: It's Titanium because the atomic number is the number of protons.

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Calculate the molarity of (3.25 mol of LiCl in 2.78 L solution

alisha [4.7K]

$\text{Morality}= \dfrac{\text{Number of moles}}{\text{Volume}}=\dfrac{3.25}{2.78}=1.169 ~mol/L$

8 0

2 years ago

why does ice float on water? the temperature of ice is lower than the temperature of water. the temperature of water and ice are

Andrew [12]

The density of ice is less than the density of water.

Fun fact: Water is the only known liquid that has this change it density.

4 0

4 years ago

Read 2 more answers

What is the graph of the orange line and is it a positive or negative connotation

dimulka [17.4K]

Answer:

Positive

Explanation:

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3 years ago

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

$CuBr\rightleftharpoons Cu^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][Br^-]$

$4.2\times 10^{-8}=0.073\times [Br^-]$

$[Br^-]=5.75\times 10^{-7}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgBr\rightleftharpoons Ag^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][Br^-]$

$7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M$

$[Ag^+]=1.34\times 10^{-6}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{1.34\times 10^{-6}}{0.073}\times 100$

Percent of $Ag^+$ remains = 0.0018 %

3 0

3 years ago

the radius of magnesium atom is 0.160nm. the radius of a magnesium ion is 7.2x 10^-11m. explain the difference in size between t

Allushta [10]

Answer:

during reaction magnesium lises ions.

Explanation:

magnesium reacts by losing two ions which makes it smaller in size.

8 0

3 years ago