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kozerog [31]
3 years ago
14

What acid has a dissociation constant of 4.57x10^-3

Chemistry
1 answer:
Artyom0805 [142]3 years ago
6 0
The acid Ka (Gallic )
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How many grams of sodium hydroxide are needed to make 500mLs of a 0.125M NaOH solution?
zubka84 [21]
Hope this helps you.

8 0
3 years ago
Bill, a lab technician, was asked to measure out sodium hydroxide (NaOH) for an experiment in a research lab. He was given a cho
Aleks04 [339]

Answer:

He is wrong . Most accurate is Buret .

Explanation:

The number of significant figure denotes the level of accuracy of a measurement .

Beaker can measure liquid in mL upto significant figure of 2 . That means it can measure volume in terms of 10 , 20 , 30mL etc . It can not measure 25 mL

accurately . The last figure of 28 mL is read by guess in the question . So it is not an accurate measurement .

Similarly , graduated cylinder can measure liquid upto significant figure of 3 .  That means it can measure volume in terms of 11 , 22 , 33 mL etc . It can not measure 25.5  mL accurately . The last figure of 28.3  mL is read by guess in the question . So it is less  accurate measurement .

Similarly , buret  can measure liquid upto significant figure of 4 .  That means it can measure volume in terms of 11.2 , 22.3 , 33.5 mL etc . It can not measure 25.53  mL accurately . The last figure of 28.32  mL is read by guess in the question . So it is most accurate among all the three instrument because it can measure accurately mL upto one tenth of it .

7 0
3 years ago
32.33 mL of 1.031 M potassium hydroxide were required to reach the endpoint of a titration of 50.00 mL of nitric acid. What was
tester [92]

The molar concentration of the nitric acid solution was 0.6666 mol/L.

<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O

<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)

= 33.33 mmol KOH

<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)

= 33.33 mmol HNO_3

<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL

= 0.6666 mol/L

4 0
3 years ago
Why would the cell membrane shrink when the cells were placed in the 4% salt solution?
Elanso [62]
In a salt solution, the water potential is lower than that in the cell. In this case, water molecules will flow from a region of higher water potential to a region of lower water potential by osmosis. Which where water molecules is now flowing out of the cell to the salt solution. Because the cell lose so much water that it now shrinks.
Osmosis is where water molecules move down the water potential gradient through a semi permeable membrane, which is the cell membrane in this case.
8 0
3 years ago
(17.ooo+2.30)x1.0100=
Dmitry [639]

Answer:

19.493

Explanation:

6 0
2 years ago
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