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beks73 [17]
3 years ago
15

I Learn Simplify the expression completely.

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

Answer: 3/8

Step-by-step explanation:1/2 divided by 4/3 is equal to 1/2 x 3/4 (you cannot divide by a fraction, you must multiply by it’s reciprocal- flip it, or cross multiply. Here we are flipping it)

Now multiply across the top ( numerators)

And then across the bottom (denominators)

1x3=3

2x4=8

Answer is 3/8

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45/100 in simplest form
Harrizon [31]
Hello there! How are you today?

First, let's take a look at our numbers.

45 / 100

Both of these numbers have a 0 and a 5, which means it is divisible by 5.
Let's divide both of them by 5.

45 / 5 = 9
100 / 5 = 20

We are now left with 9/20.

This is your simplified fraction since 9 and 20 do not have any common factors.

I hope this helps!
4 0
4 years ago
I need help with 7th grade math please 30 points need help ASAP + brainleist
Gwar [14]

Answer:

See below ~

Step-by-step explanation:

<u>Circle 1</u>

  • Circumference = 2πr = 2 x 3.14 x 2.5 = 5 x 3.14 = 15.7 m
  • Area = πr² = 3.14 x (2.5)² = 3.14 x 6.25 = 19.625 m²

<u>Circle 2</u>

  • Area = πr² = 3.14 x 1² = 3.14 mm²
  • Circumference = 2πr = 2 x 3.14 x 1 = 6.28 mm
5 0
2 years ago
Read 2 more answers
Which<br> expression is equivalent to 9q^2 - 2/3 (3q - 7) + 5q^2?
nikitadnepr [17]

Answer:

14q^2−2q+14/3

Step-by-step explanation:

9q^2 - 2/3 (3q - 7) + 5q^2

Use the distributive property to multiply -2/3 by 3q−7.

9q^2 - 2q + 14/3 + 5q^2

Combine 9q^2 and 5q^2 to get 14q^2

14q^2−2q+14/3

3 0
3 years ago
Can someone help me with this problem
Yuri [45]

Answer:

For this problem, simply substitute x in y=2(3)^x with the given x-values. The resulting coordinates should be (-3,2/27), (-2,2/9), (-1,2/3), (0,2), (1,6), (2,18), and (3,54). Now, you can plot the points, in order to get the exponential graph.

7 0
3 years ago
Pls I need help with this
LiRa [457]

Answer:

third side = 4

Step-by-step explanation:

third side is hypoenuse as it is opposite to 90 degree.

using pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

2^2 + (2\sqrt{3 )^2 = hypotenuse^2

4 + 4*3 = hypotenuse^2

16 = hypotenuse^2

\sqrt{16} = hypotenuse

4 = hypotensue

7 0
3 years ago
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