13. $9 because 75%=3/4 and 1/4 of 12 is 3, and so you multiply $3 by 3 to get $9
14. Multiply 325 by .2 to get $65.00
15. 15 minutes, because if it rises 2 feet every hour, then it rises 1 foot every hour, and so you divide that by 2 to get 15
Answers:
13. $9
14. $65.00
15. 15 mins
This might be wrong but I got 120/1008
Answer:
¾
Step-by-step explanation:
Length of Kerry string = 7(½) = 15/2
Length of John string = 6(¾) = 27/4
15/2 - 27/4
30 - 27/4
3/4
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
Answer:
-1
f (x) = -3(x + 5)
Step-by-step explanation:
1) in f(x) = 1/3x-5, replace f(x)= with y= as follows: y = (1/3)x - 5
2) interchange x and y, obtaining: x = (1/3)y - 5
3) solve this result for y: (1/3)y = -x - 5, or -(x + 5). Next, multiply both sides by 3 to eliminate the fraction (1/3): y = -3(x + 5)
4) replace y with the symbol for "inverse of f(x);
-1
f (x) = -3(x + 5)
