Question

Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what time did Ariel's brother catch up with Ariel?

Answer 1

Answer:

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

Ariel's linear equation is

$y=45x+90$ ----> equation A

Ariel's brother linear equation is

$y=60x$ ----> equation B

Equate equation A and equation B

$60x=45x+90$

Solve for x

$60x-45x=90$

$15x=90$

$x=6\ hours$

Adds 11:00 am + 6 hours=17:00 =5:00 pm