Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2
Answer:
Explanation:
height of the building h = 15 m
initial vertical velocity u = 0
v² = u² + 2 g h
u = 0 , final velocity after falling height h
h = 15
v² = 2 x 9.8 x 15
v = 17.14 m /s
. Time of fall be t
h = 1/2 g t²
15 = 1/2 x 9.8 x t²
t = 1.749 s
This time will be required for truck to come under the building .
speed = distance / time
distance = speed x time
= 22 x 1.749
38.5 m
Truck should be at a distance of 38.5 m . when the stuntman starts falling .
Answer:
Velocity
Explanation:
Velocity is a speed with a direction.
That would be
cold water
google will tell you, lol
