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timofeeve [1]
3 years ago
11

To a stationary, a bus moves south with a speed of 15 m/s. a man inside walks toward the front of the bus with a speed of 0.2 m/

s relative to the bus. What is the velocity of the man according to a stationary observer?
Physics
2 answers:
marta [7]3 years ago
8 0
It is 15.2 m/s South.
Alenkasestr [34]3 years ago
3 0

Answer:

Velocity of man with respect to stationary observer is 15.2 m/s

Explanation:

It is given that, to a stationary, a bus moves south with a speed of 15 m/s. A man inside walks toward the front of the bus with a speed of 0.2 m/s relative to the bus. We have to find the velocity of man according to stationary observer.

The velocity of bus and man are in same direction. So, the velocity of man with respect to stationary observer will be :

v_{m,o}=v_b+v_m

v_{m,o}=15\ m/s+0.2\ m/s

v_{m,o}=15.2\ m/s

Hence, this is the required solution.                 

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Answer:

When both initial speed and initial displacement is doubled then amplitude will be doubled.

Explanation:

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So,

     Formula of Simple harmonic oscillator is  X=A\sin\ (2\pi ft +\phi)  ...........(1)

                                                            Where X = Position in (m,cm,km.....)

                                                                        A = Amplitude  in (m,cm,km.....)

                                                                        F = Frequency in (Hz)

                                                                        T = Time in (sec.)

                                                                        Ф = Phase in (rad)

  For initial displacement taking t=0 we get,

                          Initial displacement = A\sin(\phi)    .................(2)            

Now taking equation (1) and differentiating it w.r.t to (t) we get

                                \frac{dx}{dt} = 2\pi fA\cos\ (2\pi ft+\phi)

                                 V= 2\pi fA\cos\ (2\pi ft+\phi)

taking t=0 for initial speed then we get,

                                Initial speed = 2\pi fA\cos\phi    ...............(3)

observing equation (2) & (3) that the initial displacement and initial speed depends on the Amplitude of the Oscillator.

Hence,

when both initial speed and displacement is doubled then amplitude will be doubled.

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