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Marat540 [252]
3 years ago
7

Please help i need to move on:(

Mathematics
2 answers:
leonid [27]3 years ago
7 0
I think it’s the second one
Yakvenalex [24]3 years ago
7 0
Should be C
1(two-thirds)
2(state legislature)
I’m sorry if I’m wrong, I’ll comment if I find out it’s wrong
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Point C has a _____ abscissa and a _____ ordinate.
VladimirAG [237]

Answer:

i think its b but im not that sure

Step-by-step explanation:

5 0
2 years ago
The answer to all 11.
madam [21]

Answer:

The rate of the current is 2 miles per hour.

Step-by-step explanation:

Let us assume that the rate of the river is v miles per hour.

The speed of the boat is 12 miles per hour.

Let us assume also that the boat can go 21 miles in t hours in the downstream and 15 miles upstream at the same time i.e. t hours.

So, from the condition given we can write that  

12 + v = \frac{21}{t} ......... (1), and  

12-v =\frac{15}{t} ......... (2)

Now, adding those two equations we get  

24 = \frac{21}{t} +\frac{15}{t} = \frac{36}{t}

⇒ t = \frac{3}{2} hours

Now, from equation (1), we get,  

12 + v = \frac{21}{\frac{3}{2} } =14

⇒ v = 2 miles per hour

Therefore, the rate of the current is 2 miles per hour. (Answer)

8 0
3 years ago
HELP PLEASE AND THANK YOU 1JAAB
Dafna1 [17]

Answer:

\bold{Q1}\ side\ BD\\\\\bold{Q2}\ \angle5\ \leftrightarrow\ \angle6\\\\\bold{Q3}\ \triangle TAP\\\\\bold{Q4}\ \triangle APT

Step-by-step explanation:

For Q1 and Q2

\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U

\overline{AB}\ \leftrightarrow\ \overline{AC}\\\overline{BD}\ \leftrightarrow\ \overline{CD}\\\\\overline{RS}\ \leftrightarrow\ \overline{TU}\\\overline{ST}\ \leftrightarrow\ \overline{UR}

For Q3 and Q4

O\ \leftrightarrow\ T\\B\ \leftrightarrow\ A\\R\ \leftrightarrow\ P\\\\E\ \leftrightarrow\ X\\F\ \leftrightarrow\ W\\D\ \leftrightarrow\ T

4 0
3 years ago
Hong made 2 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for both necklaces wa
egoroff_w [7]
B+ p= 10.40
b=2x 2.50
Now using substitution method replace b in first equation with value of second equation basically combing the two equations into one do you end up with one variable to solve .
2 x 2.50 +p =10.40
5 + p=10.40
P=$5.40
b =$5.00
The answer is EACH pendant cost $2.70
(You have to divide 5.40 by two )
6 0
2 years ago
Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe
valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0
2 years ago
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